发布时间:2019-09-16 07:35:21编辑:auto阅读(2318)
例如:时间格式是
2020-01-29 16:31:31和2025-01-23 15:30:30,怎么求得两个时间相减的时间差?
具体如下:
import time as t
import datetime as d
#定义时间差函数
def myDate(date1, date2):
date1 = t.strptime(date1, "%Y-%m-%d %H:%M:%S")
date2 = t.strptime(date2, "%Y-%m-%d %H:%M:%S")
startTime = t.strftime("%Y-%m-%d %H:%M:%S", date1)
endTime = t.strftime("%Y-%m-%d %H:%M:%S", date2)
startTime = d.datetime.strptime(startTime,"%Y-%m-%d %H:%M:%S")
endTime = d.datetime.strptime(endTime,"%Y-%m-%d %H:%M:%S")
date = endTime- startTime
return date
#参数赋值
date1 = "2020-01-29 16:31:31"
date2 = "2025-01-23 15:30:30"
#获得时间差秒数
seconds = myDate(date1, date2).seconds
#获得时间差
date = myDate(date1, date2)
print(seconds)
print(date)
上一篇: python升级2.6到2.7
下一篇: mac安装python-ldap
51675
51334
41766
38545
33020
30039
28709
23692
23612
21974
2162°
2865°
2388°
2330°
2870°
2342°
3131°
5138°
4968°
3546°